First I apologize of this has been addressed elsewhere and is redundant.
I updated to GB 2.3.3 OTA on my droid X. Although I still see the super user icon, as expected I lost root, as apps needing root (e.g. wireless tether) will not run. Before the update I used z4root given its ease. As z4 seemingly will not root GB, I tried GingerBreak from the xda-developers site as it is seemingly just a easy. However, GingerBreak will not root my droidx. It gets hung and never reboots or roots (I may try to run it again later and let it go for a good while since some reported it took awhile, although I've seen it to be unsuccessful with .596)
Anyway, to the the point. I'm seeing there may be no way to root OTA gingerbread. I see some can install the leaked GB that was rooted. However, the only instructions I see for this are if you are in Froyo still. How can I install a rooted version of GB? I just wanted to make sure I do this correctly as to not brick my phone by doing something stupid (like getting ota gb before researching root options) Any help is much appreciated.
I updated to GB 2.3.3 OTA on my droid X. Although I still see the super user icon, as expected I lost root, as apps needing root (e.g. wireless tether) will not run. Before the update I used z4root given its ease. As z4 seemingly will not root GB, I tried GingerBreak from the xda-developers site as it is seemingly just a easy. However, GingerBreak will not root my droidx. It gets hung and never reboots or roots (I may try to run it again later and let it go for a good while since some reported it took awhile, although I've seen it to be unsuccessful with .596)
Anyway, to the the point. I'm seeing there may be no way to root OTA gingerbread. I see some can install the leaked GB that was rooted. However, the only instructions I see for this are if you are in Froyo still. How can I install a rooted version of GB? I just wanted to make sure I do this correctly as to not brick my phone by doing something stupid (like getting ota gb before researching root options) Any help is much appreciated.